20z^2-44z-48=0

Solution for 20z^2-44z-48=0 equation:

20z^2-44z-48=0

a = 20; b = -44; c = -48;
Δ = b2-4ac
Δ = -442-4·20·(-48)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-76}{2*20}=\frac{-32}{40}
=-4/5
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+76}{2*20}=\frac{120}{40}
=3
$